(3x+28)+(5x+52)+(2x-10)=180

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Solution for (3x+28)+(5x+52)+(2x-10)=180 equation: 



(3x+28)+(5x+52)+(2x-10)=180

We move all terms to the left:

(3x+28)+(5x+52)+(2x-10)-(180)=0

We get rid of parentheses

3x+5x+2x+28+52-10-180=0

We add all the numbers together, and all the variables

10x-110=0

We move all terms containing x to the left, all other terms to the right

10x=110

x=110/10

x=11

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