(3x+28)+5x+52)+(2x-10)=180

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Solution for (3x+28)+5x+52)+(2x-10)=180 equation: 



(3x+28)+5x+52)+(2x-10)=180

We move all terms to the left:

(3x+28)+5x+52)+(2x-10)-(180)=0

We add all the numbers together, and all the variables

5x+(3x+28)+52)+(2x=0

We get rid of parentheses

5x+3x+52)+(2x+28=0

We add all the numbers together, and all the variables

8x+52)+(2x+28=0

We move all terms containing x to the left, all other terms to the right

8x+52)+(2x=-28

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