(3x+28)=(2x-10)

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Solution for (3x+28)=(2x-10) equation: 



(3x+28)=(2x-10)

We move all terms to the left:

(3x+28)-((2x-10))=0

We get rid of parentheses

3x-((2x-10))+28=0



We calculate terms in parentheses: -((2x-10)), so:

(2x-10)

We get rid of parentheses

2x-10

Back to the equation:

-(2x-10)



We get rid of parentheses

3x-2x+10+28=0

We add all the numbers together, and all the variables

x+38=0

We move all terms containing x to the left, all other terms to the right

x=-38

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