(3x+28)=(5x-12)

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Solution for (3x+28)=(5x-12) equation: 



(3x+28)=(5x-12)

We move all terms to the left:

(3x+28)-((5x-12))=0

We get rid of parentheses

3x-((5x-12))+28=0



We calculate terms in parentheses: -((5x-12)), so:

(5x-12)

We get rid of parentheses

5x-12

Back to the equation:

-(5x-12)



We get rid of parentheses

3x-5x+12+28=0

We add all the numbers together, and all the variables

-2x+40=0

We move all terms containing x to the left, all other terms to the right

-2x=-40

x=-40/-2

x=+20

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