(3x+29)+(10x+5)=180

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Solution for (3x+29)+(10x+5)=180 equation: 



(3x+29)+(10x+5)=180

We move all terms to the left:

(3x+29)+(10x+5)-(180)=0

We get rid of parentheses

3x+10x+29+5-180=0

We add all the numbers together, and all the variables

13x-146=0

We move all terms containing x to the left, all other terms to the right

13x=146

x=146/13

x=11+3/13

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