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(3x+3)(2x+5)=(1.5x+5)(4x+2)
We move all terms to the left:
(3x+3)(2x+5)-((1.5x+5)(4x+2))=0
We multiply parentheses ..
(+6x^2+15x+6x+15)-((1.5x+5)(4x+2))=0
We calculate terms in parentheses: -((1.5x+5)(4x+2)), so:We get rid of parentheses
(1.5x+5)(4x+2)
We multiply parentheses ..
(+4x^2+2x+20x+10)
We get rid of parentheses
4x^2+2x+20x+10
We add all the numbers together, and all the variables
4x^2+22x+10
Back to the equation:
-(4x^2+22x+10)
6x^2-4x^2+15x+6x-22x+15-10=0
We add all the numbers together, and all the variables
2x^2-1x+5=0
a = 2; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·2·5
Δ = -39
Delta is less than zero, so there is no solution for the equation
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