(3x+3)(3x+3)=5+x(8+x)

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Solution for (3x+3)(3x+3)=5+x(8+x) equation: 



(3x+3)(3x+3)=5+x(8+x)

We move all terms to the left:

(3x+3)(3x+3)-(5+x(8+x))=0

We add all the numbers together, and all the variables

(3x+3)(3x+3)-(5+x(x+8))=0

We multiply parentheses ..

(+9x^2+9x+9x+9)-(5+x(x+8))=0



We calculate terms in parentheses: -(5+x(x+8)), so:

5+x(x+8)

determiningTheFunctionDomain
x(x+8)+5

We multiply parentheses

x^2+8x+5

Back to the equation:

-(x^2+8x+5)



We get rid of parentheses

9x^2-x^2+9x+9x-8x+9-5=0

We add all the numbers together, and all the variables

8x^2+10x+4=0

a = 8; b = 10; c = +4;
Δ = b2-4ac
Δ = 102-4·8·4
Δ = -28
Delta is less than zero, so there is no solution for the equation

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