(3x+3)(4x-4)=0

Solution for (3x+3)(4x-4)=0 equation:

Simplifying
(3x + 3)(4x + -4) = 0

Reorder the terms:
(3 + 3x)(4x + -4) = 0

Reorder the terms:
(3 + 3x)(-4 + 4x) = 0

Multiply (3 + 3x) * (-4 + 4x)
(3(-4 + 4x) + 3x * (-4 + 4x)) = 0
((-4 * 3 + 4x * 3) + 3x * (-4 + 4x)) = 0
((-12 + 12x) + 3x * (-4 + 4x)) = 0
(-12 + 12x + (-4 * 3x + 4x * 3x)) = 0
(-12 + 12x + (-12x + 12x2)) = 0

Combine like terms: 12x + -12x = 0
(-12 + 0 + 12x2) = 0
(-12 + 12x2) = 0

Solving
-12 + 12x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 12x2 = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 12x2 = 0 + 12
12x2 = 0 + 12

Combine like terms: 0 + 12 = 12
12x2 = 12

Divide each side by '12'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}