(3x+3)(x)=112

Solution for (3x+3)(x)=112 equation:

(3x+3)(x)=112

We move all terms to the left:

(3x+3)(x)-(112)=0

We multiply parentheses

3x^2+3x-112=0

a = 3; b = 3; c = -112;
Δ = b2-4ac
Δ = 32-4·3·(-112)
Δ = 1353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1353}}{2*3}=\frac{-3-\sqrt{1353}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1353}}{2*3}=\frac{-3+\sqrt{1353}}{6}
$