(3x+3)+(4x+1)+(3x+3)+(4x+1)=120

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Solution for (3x+3)+(4x+1)+(3x+3)+(4x+1)=120 equation:



(3x+3)+(4x+1)+(3x+3)+(4x+1)=120
We move all terms to the left:
(3x+3)+(4x+1)+(3x+3)+(4x+1)-(120)=0
We get rid of parentheses
3x+4x+3x+4x+3+1+3+1-120=0
We add all the numbers together, and all the variables
14x-112=0
We move all terms containing x to the left, all other terms to the right
14x=112
x=112/14
x=8

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