(3x+3)+(4x+1)+(3x+3)+(4x+1)=120

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Solution for (3x+3)+(4x+1)+(3x+3)+(4x+1)=120 equation: 



(3x+3)+(4x+1)+(3x+3)+(4x+1)=120

We move all terms to the left:

(3x+3)+(4x+1)+(3x+3)+(4x+1)-(120)=0

We get rid of parentheses

3x+4x+3x+4x+3+1+3+1-120=0

We add all the numbers together, and all the variables

14x-112=0

We move all terms containing x to the left, all other terms to the right

14x=112

x=112/14

x=8

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