(3x+3)+(4x+1)=120

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Solution for (3x+3)+(4x+1)=120 equation: 



(3x+3)+(4x+1)=120

We move all terms to the left:

(3x+3)+(4x+1)-(120)=0

We get rid of parentheses

3x+4x+3+1-120=0

We add all the numbers together, and all the variables

7x-116=0

We move all terms containing x to the left, all other terms to the right

7x=116

x=116/7

x=16+4/7

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