(3x+3)/2=19-(5x+5)/3

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Solution for (3x+3)/2=19-(5x+5)/3 equation: 



(3x+3)/2=19-(5x+5)/3

We move all terms to the left:

(3x+3)/2-(19-(5x+5)/3)=0

We calculate fractions


3x/()+(-(19-(5x+5)*2)/()=0



We calculate terms in parentheses: +(-(19-(5x+5)*2)/(), so:

-(19-(5x+5)*2)/(

We multiply all the terms by the denominator


-(19-(5x+5)*2)



We calculate terms in parentheses: -(19-(5x+5)*2), so:

19-(5x+5)*2

determiningTheFunctionDomain
-(5x+5)*2+19

We multiply parentheses

-10x-10+19

We add all the numbers together, and all the variables

-10x+9

Back to the equation:

-(-10x+9)



We get rid of parentheses

10x-9

Back to the equation:

+(10x-9)



We get rid of parentheses

3x/()+10x-9=0

We multiply all the terms by the denominator


3x+10x*()-9*()=0

We add all the numbers together, and all the variables

3x+10x*()=0

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