(3x+3)=(x+32)

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Solution for (3x+3)=(x+32) equation: 



(3x+3)=(x+32)

We move all terms to the left:

(3x+3)-((x+32))=0

We get rid of parentheses

3x-((x+32))+3=0



We calculate terms in parentheses: -((x+32)), so:

(x+32)

We get rid of parentheses

x+32

Back to the equation:

-(x+32)



We get rid of parentheses

3x-x-32+3=0

We add all the numbers together, and all the variables

2x-29=0

We move all terms containing x to the left, all other terms to the right

2x=29

x=29/2

x=14+1/2

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