(3x+3)=3(2-3x)+6

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Solution for (3x+3)=3(2-3x)+6 equation: 



(3x+3)=3(2-3x)+6

We move all terms to the left:

(3x+3)-(3(2-3x)+6)=0

We add all the numbers together, and all the variables

(3x+3)-(3(-3x+2)+6)=0

We get rid of parentheses

3x-(3(-3x+2)+6)+3=0



We calculate terms in parentheses: -(3(-3x+2)+6), so:

3(-3x+2)+6

We multiply parentheses

-9x+6+6

We add all the numbers together, and all the variables

-9x+12

Back to the equation:

-(-9x+12)



We get rid of parentheses

3x+9x-12+3=0

We add all the numbers together, and all the variables

12x-9=0

We move all terms containing x to the left, all other terms to the right

12x=9

x=9/12

x=3/4

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