(3x+3)=3(2x+2)

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Solution for (3x+3)=3(2x+2) equation: 



(3x+3)=3(2x+2)

We move all terms to the left:

(3x+3)-(3(2x+2))=0

We get rid of parentheses

3x-(3(2x+2))+3=0



We calculate terms in parentheses: -(3(2x+2)), so:

3(2x+2)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

3x-6x-6+3=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1

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