(3x+3)=3(2x+2)

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Solution for (3x+3)=3(2x+2) equation:



(3x+3)=3(2x+2)
We move all terms to the left:
(3x+3)-(3(2x+2))=0
We get rid of parentheses
3x-(3(2x+2))+3=0
We calculate terms in parentheses: -(3(2x+2)), so:
3(2x+2)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
We get rid of parentheses
3x-6x-6+3=0
We add all the numbers together, and all the variables
-3x-3=0
We move all terms containing x to the left, all other terms to the right
-3x=3
x=3/-3
x=-1

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