(3x+30)+(3x-10)=180

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Solution for (3x+30)+(3x-10)=180 equation: 



(3x+30)+(3x-10)=180

We move all terms to the left:

(3x+30)+(3x-10)-(180)=0

We get rid of parentheses

3x+3x+30-10-180=0

We add all the numbers together, and all the variables

6x-160=0

We move all terms containing x to the left, all other terms to the right

6x=160

x=160/6

x=26+2/3

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