(3x+32)=2(x+25)

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Solution for (3x+32)=2(x+25) equation: 



(3x+32)=2(x+25)

We move all terms to the left:

(3x+32)-(2(x+25))=0

We get rid of parentheses

3x-(2(x+25))+32=0



We calculate terms in parentheses: -(2(x+25)), so:

2(x+25)

We multiply parentheses

2x+50

Back to the equation:

-(2x+50)



We get rid of parentheses

3x-2x-50+32=0

We add all the numbers together, and all the variables

x-18=0

We move all terms containing x to the left, all other terms to the right

x=18

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