(3x+33)=(4x+8)

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Solution for (3x+33)=(4x+8) equation: 



(3x+33)=(4x+8)

We move all terms to the left:

(3x+33)-((4x+8))=0

We get rid of parentheses

3x-((4x+8))+33=0



We calculate terms in parentheses: -((4x+8)), so:

(4x+8)

We get rid of parentheses

4x+8

Back to the equation:

-(4x+8)



We get rid of parentheses

3x-4x-8+33=0

We add all the numbers together, and all the variables

-1x+25=0

We move all terms containing x to the left, all other terms to the right

-x=-25

x=-25/-1

x=+25

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