(3x+33)=(6x+11)

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Solution for (3x+33)=(6x+11) equation: 



(3x+33)=(6x+11)

We move all terms to the left:

(3x+33)-((6x+11))=0

We get rid of parentheses

3x-((6x+11))+33=0



We calculate terms in parentheses: -((6x+11)), so:

(6x+11)

We get rid of parentheses

6x+11

Back to the equation:

-(6x+11)



We get rid of parentheses

3x-6x-11+33=0

We add all the numbers together, and all the variables

-3x+22=0

We move all terms containing x to the left, all other terms to the right

-3x=-22

x=-22/-3

x=7+1/3

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