(3x+34)=(12x+33)

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Solution for (3x+34)=(12x+33) equation: 



(3x+34)=(12x+33)

We move all terms to the left:

(3x+34)-((12x+33))=0

We get rid of parentheses

3x-((12x+33))+34=0



We calculate terms in parentheses: -((12x+33)), so:

(12x+33)

We get rid of parentheses

12x+33

Back to the equation:

-(12x+33)



We get rid of parentheses

3x-12x-33+34=0

We add all the numbers together, and all the variables

-9x+1=0

We move all terms containing x to the left, all other terms to the right

-9x=-1

x=-1/-9

x=1/9

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