(3x+35)=(4x+20)

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Solution for (3x+35)=(4x+20) equation: 



(3x+35)=(4x+20)

We move all terms to the left:

(3x+35)-((4x+20))=0

We get rid of parentheses

3x-((4x+20))+35=0



We calculate terms in parentheses: -((4x+20)), so:

(4x+20)

We get rid of parentheses

4x+20

Back to the equation:

-(4x+20)



We get rid of parentheses

3x-4x-20+35=0

We add all the numbers together, and all the variables

-1x+15=0

We move all terms containing x to the left, all other terms to the right

-x=-15

x=-15/-1

x=+15

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