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(3x+38)=(7x-2)
We move all terms to the left:
(3x+38)-((7x-2))=0
We get rid of parentheses
3x-((7x-2))+38=0
We calculate terms in parentheses: -((7x-2)), so:We get rid of parentheses
(7x-2)
We get rid of parentheses
7x-2
Back to the equation:
-(7x-2)
3x-7x+2+38=0
We add all the numbers together, and all the variables
-4x+40=0
We move all terms containing x to the left, all other terms to the right
-4x=-40
x=-40/-4
x=+10
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