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(3x+4)(2x+3)=(x+1)(6x+7)
We move all terms to the left:
(3x+4)(2x+3)-((x+1)(6x+7))=0
We multiply parentheses ..
(+6x^2+9x+8x+12)-((x+1)(6x+7))=0
We calculate terms in parentheses: -((x+1)(6x+7)), so:We get rid of parentheses
(x+1)(6x+7)
We multiply parentheses ..
(+6x^2+7x+6x+7)
We get rid of parentheses
6x^2+7x+6x+7
We add all the numbers together, and all the variables
6x^2+13x+7
Back to the equation:
-(6x^2+13x+7)
6x^2-6x^2+9x+8x-13x+12-7=0
We add all the numbers together, and all the variables
4x+5=0
We move all terms containing x to the left, all other terms to the right
4x=-5
x=-5/4
x=-1+1/4
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