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(3x+4)(2x+8)=56
We move all terms to the left:
(3x+4)(2x+8)-(56)=0
We multiply parentheses ..
(+6x^2+24x+8x+32)-56=0
We get rid of parentheses
6x^2+24x+8x+32-56=0
We add all the numbers together, and all the variables
6x^2+32x-24=0
a = 6; b = 32; c = -24;
Δ = b2-4ac
Δ = 322-4·6·(-24)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-40}{2*6}=\frac{-72}{12} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+40}{2*6}=\frac{8}{12} =2/3 $
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