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(3x+4)(3x+3)=0
We multiply parentheses ..
(+9x^2+9x+12x+12)=0
We get rid of parentheses
9x^2+9x+12x+12=0
We add all the numbers together, and all the variables
9x^2+21x+12=0
a = 9; b = 21; c = +12;
Δ = b2-4ac
Δ = 212-4·9·12
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-3}{2*9}=\frac{-24}{18} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+3}{2*9}=\frac{-18}{18} =-1 $
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