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(3x+4)(3x+4)=7
We move all terms to the left:
(3x+4)(3x+4)-(7)=0
We multiply parentheses ..
(+9x^2+12x+12x+16)-7=0
We get rid of parentheses
9x^2+12x+12x+16-7=0
We add all the numbers together, and all the variables
9x^2+24x+9=0
a = 9; b = 24; c = +9;
Δ = b2-4ac
Δ = 242-4·9·9
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-6\sqrt{7}}{2*9}=\frac{-24-6\sqrt{7}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+6\sqrt{7}}{2*9}=\frac{-24+6\sqrt{7}}{18} $
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