(3x+4)(4x+10)=8x

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Solution for (3x+4)(4x+10)=8x equation: 



(3x+4)(4x+10)=8x

We move all terms to the left:

(3x+4)(4x+10)-(8x)=0

We add all the numbers together, and all the variables

-8x+(3x+4)(4x+10)=0

We multiply parentheses ..

(+12x^2+30x+16x+40)-8x=0

We get rid of parentheses

12x^2+30x+16x-8x+40=0

We add all the numbers together, and all the variables

12x^2+38x+40=0

a = 12; b = 38; c = +40;
Δ = b2-4ac
Δ = 382-4·12·40
Δ = -476
Delta is less than zero, so there is no solution for the equation

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