(3x+4)(4x-3)-5=(2x+5)(6x-7)

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Solution for (3x+4)(4x-3)-5=(2x+5)(6x-7) equation:



(3x+4)(4x-3)-5=(2x+5)(6x-7)
We move all terms to the left:
(3x+4)(4x-3)-5-((2x+5)(6x-7))=0
We multiply parentheses ..
(+12x^2-9x+16x-12)-((2x+5)(6x-7))-5=0
We calculate terms in parentheses: -((2x+5)(6x-7)), so:
(2x+5)(6x-7)
We multiply parentheses ..
(+12x^2-14x+30x-35)
We get rid of parentheses
12x^2-14x+30x-35
We add all the numbers together, and all the variables
12x^2+16x-35
Back to the equation:
-(12x^2+16x-35)
We get rid of parentheses
12x^2-12x^2-9x+16x-16x-12+35-5=0
We add all the numbers together, and all the variables
-9x+18=0
We move all terms containing x to the left, all other terms to the right
-9x=-18
x=-18/-9
x=+2

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