(3x+4)(4x-3)-5=(2x+5)(6x-7)

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Solution for (3x+4)(4x-3)-5=(2x+5)(6x-7) equation: 



(3x+4)(4x-3)-5=(2x+5)(6x-7)

We move all terms to the left:

(3x+4)(4x-3)-5-((2x+5)(6x-7))=0

We multiply parentheses ..

(+12x^2-9x+16x-12)-((2x+5)(6x-7))-5=0



We calculate terms in parentheses: -((2x+5)(6x-7)), so:

(2x+5)(6x-7)

We multiply parentheses ..

(+12x^2-14x+30x-35)

We get rid of parentheses

12x^2-14x+30x-35

We add all the numbers together, and all the variables

12x^2+16x-35

Back to the equation:

-(12x^2+16x-35)



We get rid of parentheses

12x^2-12x^2-9x+16x-16x-12+35-5=0

We add all the numbers together, and all the variables

-9x+18=0

We move all terms containing x to the left, all other terms to the right

-9x=-18

x=-18/-9

x=+2

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