(3x+4)(5x+1)(2x+5)=(2x)(x+13)

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Solution for (3x+4)(5x+1)(2x+5)=(2x)(x+13) equation: 



(3x+4)(5x+1)(2x+5)=(2x)(x+13)

We move all terms to the left:

(3x+4)(5x+1)(2x+5)-((2x)(x+13))=0

We multiply parentheses ..

(+15x^2+3x+20x+4)(2x+5)-(2x(x+13))=0



We calculate terms in parentheses: -(2x(x+13)), so:

2x(x+13)

We multiply parentheses

2x^2+26x

Back to the equation:

-(2x^2+26x)



We get rid of parentheses

(+15x^2+3x+20x+4)(2x+5)-2x^2-26x=0

We add all the numbers together, and all the variables

-2x^2+(+15x^2+3x+20x+4)(2x+5)-26x=0

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