(3x+4)(x+1)=(3x+5)(x-1)

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Solution for (3x+4)(x+1)=(3x+5)(x-1) equation:



(3x+4)(x+1)=(3x+5)(x-1)
We move all terms to the left:
(3x+4)(x+1)-((3x+5)(x-1))=0
We multiply parentheses ..
(+3x^2+3x+4x+4)-((3x+5)(x-1))=0
We calculate terms in parentheses: -((3x+5)(x-1)), so:
(3x+5)(x-1)
We multiply parentheses ..
(+3x^2-3x+5x-5)
We get rid of parentheses
3x^2-3x+5x-5
We add all the numbers together, and all the variables
3x^2+2x-5
Back to the equation:
-(3x^2+2x-5)
We get rid of parentheses
3x^2-3x^2+3x+4x-2x+4+5=0
We add all the numbers together, and all the variables
5x+9=0
We move all terms containing x to the left, all other terms to the right
5x=-9
x=-9/5
x=-1+4/5

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