(3x+4)(x-5)=(3x+4)(x-7)

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Solution for (3x+4)(x-5)=(3x+4)(x-7) equation: 



(3x+4)(x-5)=(3x+4)(x-7)

We move all terms to the left:

(3x+4)(x-5)-((3x+4)(x-7))=0

We multiply parentheses ..

(+3x^2-15x+4x-20)-((3x+4)(x-7))=0



We calculate terms in parentheses: -((3x+4)(x-7)), so:

(3x+4)(x-7)

We multiply parentheses ..

(+3x^2-21x+4x-28)

We get rid of parentheses

3x^2-21x+4x-28

We add all the numbers together, and all the variables

3x^2-17x-28

Back to the equation:

-(3x^2-17x-28)



We get rid of parentheses

3x^2-3x^2-15x+4x+17x-20+28=0

We add all the numbers together, and all the variables

6x+8=0

We move all terms containing x to the left, all other terms to the right

6x=-8

x=-8/6

x=-1+1/3

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