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(3x+4)(4x+3)=(2x+6)(6x+2)
We move all terms to the left:
(3x+4)(4x+3)-((2x+6)(6x+2))=0
We multiply parentheses ..
(+12x^2+9x+16x+12)-((2x+6)(6x+2))=0
We calculate terms in parentheses: -((2x+6)(6x+2)), so:We get rid of parentheses
(2x+6)(6x+2)
We multiply parentheses ..
(+12x^2+4x+36x+12)
We get rid of parentheses
12x^2+4x+36x+12
We add all the numbers together, and all the variables
12x^2+40x+12
Back to the equation:
-(12x^2+40x+12)
12x^2-12x^2+9x+16x-40x+12-12=0
We add all the numbers together, and all the variables
-15x=0
x=0/-15
x=0
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