(3x+4)+(10x-19)=180

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Solution for (3x+4)+(10x-19)=180 equation:



(3x+4)+(10x-19)=180
We move all terms to the left:
(3x+4)+(10x-19)-(180)=0
We get rid of parentheses
3x+10x+4-19-180=0
We add all the numbers together, and all the variables
13x-195=0
We move all terms containing x to the left, all other terms to the right
13x=195
x=195/13
x=15

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