(3x+4)+(2x+1)=(6x-7)

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Solution for (3x+4)+(2x+1)=(6x-7) equation: 



(3x+4)+(2x+1)=(6x-7)

We move all terms to the left:

(3x+4)+(2x+1)-((6x-7))=0

We get rid of parentheses

3x+2x-((6x-7))+4+1=0



We calculate terms in parentheses: -((6x-7)), so:

(6x-7)

We get rid of parentheses

6x-7

Back to the equation:

-(6x-7)



We add all the numbers together, and all the variables

5x-(6x-7)+5=0

We get rid of parentheses

5x-6x+7+5=0

We add all the numbers together, and all the variables

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12

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