(3x+4)+(2x+2)=5(1x-1)+8

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Solution for (3x+4)+(2x+2)=5(1x-1)+8 equation:


Simplifying
(3x + 4) + (2x + 2) = 5(1x + -1) + 8

Reorder the terms:
(4 + 3x) + (2x + 2) = 5(1x + -1) + 8

Remove parenthesis around (4 + 3x)
4 + 3x + (2x + 2) = 5(1x + -1) + 8

Reorder the terms:
4 + 3x + (2 + 2x) = 5(1x + -1) + 8

Remove parenthesis around (2 + 2x)
4 + 3x + 2 + 2x = 5(1x + -1) + 8

Reorder the terms:
4 + 2 + 3x + 2x = 5(1x + -1) + 8

Combine like terms: 4 + 2 = 6
6 + 3x + 2x = 5(1x + -1) + 8

Combine like terms: 3x + 2x = 5x
6 + 5x = 5(1x + -1) + 8

Reorder the terms:
6 + 5x = 5(-1 + 1x) + 8
6 + 5x = (-1 * 5 + 1x * 5) + 8
6 + 5x = (-5 + 5x) + 8

Reorder the terms:
6 + 5x = -5 + 8 + 5x

Combine like terms: -5 + 8 = 3
6 + 5x = 3 + 5x

Add '-5x' to each side of the equation.
6 + 5x + -5x = 3 + 5x + -5x

Combine like terms: 5x + -5x = 0
6 + 0 = 3 + 5x + -5x
6 = 3 + 5x + -5x

Combine like terms: 5x + -5x = 0
6 = 3 + 0
6 = 3

Solving
6 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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