(3x+4)+(2x-2)=64

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Solution for (3x+4)+(2x-2)=64 equation: 



(3x+4)+(2x-2)=64

We move all terms to the left:

(3x+4)+(2x-2)-(64)=0

We get rid of parentheses

3x+2x+4-2-64=0

We add all the numbers together, and all the variables

5x-62=0

We move all terms containing x to the left, all other terms to the right

5x=62

x=62/5

x=12+2/5

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