(3x+4)+(2x-3)=16

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Solution for (3x+4)+(2x-3)=16 equation:


Simplifying
(3x + 4) + (2x + -3) = 16

Reorder the terms:
(4 + 3x) + (2x + -3) = 16

Remove parenthesis around (4 + 3x)
4 + 3x + (2x + -3) = 16

Reorder the terms:
4 + 3x + (-3 + 2x) = 16

Remove parenthesis around (-3 + 2x)
4 + 3x + -3 + 2x = 16

Reorder the terms:
4 + -3 + 3x + 2x = 16

Combine like terms: 4 + -3 = 1
1 + 3x + 2x = 16

Combine like terms: 3x + 2x = 5x
1 + 5x = 16

Solving
1 + 5x = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 5x = 16 + -1

Combine like terms: 1 + -1 = 0
0 + 5x = 16 + -1
5x = 16 + -1

Combine like terms: 16 + -1 = 15
5x = 15

Divide each side by '5'.
x = 3

Simplifying
x = 3

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