(3x+4)+(3x+4)=(7x-3)

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Solution for (3x+4)+(3x+4)=(7x-3) equation: 



(3x+4)+(3x+4)=(7x-3)

We move all terms to the left:

(3x+4)+(3x+4)-((7x-3))=0

We get rid of parentheses

3x+3x-((7x-3))+4+4=0



We calculate terms in parentheses: -((7x-3)), so:

(7x-3)

We get rid of parentheses

7x-3

Back to the equation:

-(7x-3)



We add all the numbers together, and all the variables

6x-(7x-3)+8=0

We get rid of parentheses

6x-7x+3+8=0

We add all the numbers together, and all the variables

-1x+11=0

We move all terms containing x to the left, all other terms to the right

-x=-11

x=-11/-1

x=+11

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