(3x+4)+(4x+3)=8(2x+1)

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Solution for (3x+4)+(4x+3)=8(2x+1) equation:


Simplifying
(3x + 4) + (4x + 3) = 8(2x + 1)

Reorder the terms:
(4 + 3x) + (4x + 3) = 8(2x + 1)

Remove parenthesis around (4 + 3x)
4 + 3x + (4x + 3) = 8(2x + 1)

Reorder the terms:
4 + 3x + (3 + 4x) = 8(2x + 1)

Remove parenthesis around (3 + 4x)
4 + 3x + 3 + 4x = 8(2x + 1)

Reorder the terms:
4 + 3 + 3x + 4x = 8(2x + 1)

Combine like terms: 4 + 3 = 7
7 + 3x + 4x = 8(2x + 1)

Combine like terms: 3x + 4x = 7x
7 + 7x = 8(2x + 1)

Reorder the terms:
7 + 7x = 8(1 + 2x)
7 + 7x = (1 * 8 + 2x * 8)
7 + 7x = (8 + 16x)

Solving
7 + 7x = 8 + 16x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16x' to each side of the equation.
7 + 7x + -16x = 8 + 16x + -16x

Combine like terms: 7x + -16x = -9x
7 + -9x = 8 + 16x + -16x

Combine like terms: 16x + -16x = 0
7 + -9x = 8 + 0
7 + -9x = 8

Add '-7' to each side of the equation.
7 + -7 + -9x = 8 + -7

Combine like terms: 7 + -7 = 0
0 + -9x = 8 + -7
-9x = 8 + -7

Combine like terms: 8 + -7 = 1
-9x = 1

Divide each side by '-9'.
x = -0.1111111111

Simplifying
x = -0.1111111111

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