(3x+4)+(4x-2)=72

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Solution for (3x+4)+(4x-2)=72 equation: 



(3x+4)+(4x-2)=72

We move all terms to the left:

(3x+4)+(4x-2)-(72)=0

We get rid of parentheses

3x+4x+4-2-72=0

We add all the numbers together, and all the variables

7x-70=0

We move all terms containing x to the left, all other terms to the right

7x=70

x=70/7

x=10

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