(3x+4)+(5x+1)+(2x+5)=(2x)+(x+13)+(2x)+(x+13)

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Solution for (3x+4)+(5x+1)+(2x+5)=(2x)+(x+13)+(2x)+(x+13) equation: 



(3x+4)+(5x+1)+(2x+5)=(2x)+(x+13)+(2x)+(x+13)

We move all terms to the left:

(3x+4)+(5x+1)+(2x+5)-((2x)+(x+13)+(2x)+(x+13))=0

We get rid of parentheses

3x+5x+2x-(2x+(x+13)+2x+(x+13))+4+1+5=0



We calculate terms in parentheses: -(2x+(x+13)+2x+(x+13)), so:

2x+(x+13)+2x+(x+13)

We add all the numbers together, and all the variables

4x+(x+13)+(x+13)

We get rid of parentheses

4x+x+x+13+13

We add all the numbers together, and all the variables

6x+26

Back to the equation:

-(6x+26)



We add all the numbers together, and all the variables

10x-(6x+26)+10=0

We get rid of parentheses

10x-6x-26+10=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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