(3x+4)+(8x+4)=140

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Solution for (3x+4)+(8x+4)=140 equation: 



(3x+4)+(8x+4)=140

We move all terms to the left:

(3x+4)+(8x+4)-(140)=0

We get rid of parentheses

3x+8x+4+4-140=0

We add all the numbers together, and all the variables

11x-132=0

We move all terms containing x to the left, all other terms to the right

11x=132

x=132/11

x=12

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