(3x+4)+(x+1)=4(x-1)+17

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Solution for (3x+4)+(x+1)=4(x-1)+17 equation:


Simplifying
(3x + 4) + (x + 1) = 4(x + -1) + 17

Reorder the terms:
(4 + 3x) + (x + 1) = 4(x + -1) + 17

Remove parenthesis around (4 + 3x)
4 + 3x + (x + 1) = 4(x + -1) + 17

Reorder the terms:
4 + 3x + (1 + x) = 4(x + -1) + 17

Remove parenthesis around (1 + x)
4 + 3x + 1 + x = 4(x + -1) + 17

Reorder the terms:
4 + 1 + 3x + x = 4(x + -1) + 17

Combine like terms: 4 + 1 = 5
5 + 3x + x = 4(x + -1) + 17

Combine like terms: 3x + x = 4x
5 + 4x = 4(x + -1) + 17

Reorder the terms:
5 + 4x = 4(-1 + x) + 17
5 + 4x = (-1 * 4 + x * 4) + 17
5 + 4x = (-4 + 4x) + 17

Reorder the terms:
5 + 4x = -4 + 17 + 4x

Combine like terms: -4 + 17 = 13
5 + 4x = 13 + 4x

Add '-4x' to each side of the equation.
5 + 4x + -4x = 13 + 4x + -4x

Combine like terms: 4x + -4x = 0
5 + 0 = 13 + 4x + -4x
5 = 13 + 4x + -4x

Combine like terms: 4x + -4x = 0
5 = 13 + 0
5 = 13

Solving
5 = 13

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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