(3x+4)+(x+2)=4(x-1)+8

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Solution for (3x+4)+(x+2)=4(x-1)+8 equation: 


Simplifying
(3x + 4) + (x + 2) = 4(x + -1) + 8

Reorder the terms:
(4 + 3x) + (x + 2) = 4(x + -1) + 8

Remove parenthesis around (4 + 3x)
4 + 3x + (x + 2) = 4(x + -1) + 8

Reorder the terms:
4 + 3x + (2 + x) = 4(x + -1) + 8

Remove parenthesis around (2 + x)
4 + 3x + 2 + x = 4(x + -1) + 8

Reorder the terms:
4 + 2 + 3x + x = 4(x + -1) + 8

Combine like terms: 4 + 2 = 6
6 + 3x + x = 4(x + -1) + 8

Combine like terms: 3x + x = 4x
6 + 4x = 4(x + -1) + 8

Reorder the terms:
6 + 4x = 4(-1 + x) + 8
6 + 4x = (-1 * 4 + x * 4) + 8
6 + 4x = (-4 + 4x) + 8

Reorder the terms:
6 + 4x = -4 + 8 + 4x

Combine like terms: -4 + 8 = 4
6 + 4x = 4 + 4x

Add '-4x' to each side of the equation.
6 + 4x + -4x = 4 + 4x + -4x

Combine like terms: 4x + -4x = 0
6 + 0 = 4 + 4x + -4x
6 = 4 + 4x + -4x

Combine like terms: 4x + -4x = 0
6 = 4 + 0
6 = 4

Solving
6 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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