(3x+4)+(x-4)=x+16

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Solution for (3x+4)+(x-4)=x+16 equation: 



(3x+4)+(x-4)=x+16

We move all terms to the left:

(3x+4)+(x-4)-(x+16)=0

We get rid of parentheses

3x+x-x+4-4-16=0

We add all the numbers together, and all the variables

3x-16=0

We move all terms containing x to the left, all other terms to the right

3x=16

x=16/3

x=5+1/3

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