(3x+4)+45+(3x-19)=180

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Solution for (3x+4)+45+(3x-19)=180 equation:



(3x+4)+45+(3x-19)=180
We move all terms to the left:
(3x+4)+45+(3x-19)-(180)=0
We add all the numbers together, and all the variables
(3x+4)+(3x-19)-135=0
We get rid of parentheses
3x+3x+4-19-135=0
We add all the numbers together, and all the variables
6x-150=0
We move all terms containing x to the left, all other terms to the right
6x=150
x=150/6
x=25

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