(3x+4)-(x-8)=3(4x+2)-7x+10

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Solution for (3x+4)-(x-8)=3(4x+2)-7x+10 equation: 



(3x+4)-(x-8)=3(4x+2)-7x+10

We move all terms to the left:

(3x+4)-(x-8)-(3(4x+2)-7x+10)=0

We get rid of parentheses

3x-x-(3(4x+2)-7x+10)+4+8=0



We calculate terms in parentheses: -(3(4x+2)-7x+10), so:

3(4x+2)-7x+10

We add all the numbers together, and all the variables

-7x+3(4x+2)+10

We multiply parentheses

-7x+12x+6+10

We add all the numbers together, and all the variables

5x+16

Back to the equation:

-(5x+16)



We add all the numbers together, and all the variables

2x-(5x+16)+12=0

We get rid of parentheses

2x-5x-16+12=0

We add all the numbers together, and all the variables

-3x-4=0

We move all terms containing x to the left, all other terms to the right

-3x=4

x=4/-3

x=-1+1/3

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