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(3x+4)-2x=-9/(2-5x)-7x=58
We move all terms to the left:
(3x+4)-2x-(-9/(2-5x)-7x)=0
Domain of the equation: (2-5x)-7x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-5x)-7x!=-2
x!=-2/1
x!=-2
x∈R
(3x+4)-2x-(-9/(-5x+2)-7x)=0
We add all the numbers together, and all the variables
-2x+(3x+4)-(-9/(-5x+2)-7x)=0
We get rid of parentheses
-2x+3x-(-9/(-5x+2)-7x)+4=0
We multiply all the terms by the denominator
-2x*(-5x+2)-7x)+3x*(-5x+2)-7x)-(-9+4*(-5x+2)-7x)=0
We add all the numbers together, and all the variables
-10x-2x*(-5x+2)-7x)+3x*(+2)-7x)-(-9+4*(+2)-7x)=0
We multiply parentheses
10x^2-10x-4x-7x)+3x*(+2)-7x)-(-9+4*(+2)-7x)=0
We add all the numbers together, and all the variables
10x^2-10x-4x-7x)+3x*2-7x)-(-9+4*2-7x)=0
We add all the numbers together, and all the variables
10x^2-14x-7x)+3x*2-7x)-(-9+4*2-7x)=0
We add all the numbers together, and all the variables
10x^2-14x-7x)+3x*2-7x)-(-7x-1)=0
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