(3x+4)/(2x-7)=5

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Solution for (3x+4)/(2x-7)=5 equation:


D( x )

2*x-7 = 0

2*x-7 = 0

2*x-7 = 0

2*x-7 = 0 // + 7

2*x = 7 // : 2

x = 7/2

x in (-oo:7/2) U (7/2:+oo)

(3*x+4)/(2*x-7) = 5 // - 5

(3*x+4)/(2*x-7)-5 = 0

(3*x+4)/(2*x-7)+(-5*(2*x-7))/(2*x-7) = 0

3*x-5*(2*x-7)+4 = 0

39-7*x = 0

(39-7*x)/(2*x-7) = 0

(39-7*x)/(2*x-7) = 0 // * 2*x-7

39-7*x = 0

39-7*x = 0 // - 39

-7*x = -39 // : -7

x = -39/(-7)

x = 39/7

x = 39/7

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