(3x+4)/12+(x-10)/12=(x+1)/8

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Solution for (3x+4)/12+(x-10)/12=(x+1)/8 equation:



(3x+4)/12+(x-10)/12=(x+1)/8
We move all terms to the left:
(3x+4)/12+(x-10)/12-((x+1)/8)=0
We calculate fractions
4x/()+(-((x+1)*12)/()=0
We calculate terms in parentheses: +(-((x+1)*12)/(), so:
-((x+1)*12)/(
We multiply all the terms by the denominator
-((x+1)*12)
We calculate terms in parentheses: -((x+1)*12), so:
(x+1)*12
We multiply parentheses
12x+12
Back to the equation:
-(12x+12)
We get rid of parentheses
-12x-12
Back to the equation:
+(-12x-12)
We get rid of parentheses
4x/()-12x-12=0
We multiply all the terms by the denominator
4x-12x*()-12*()=0
We add all the numbers together, and all the variables
4x-12x*()=0

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